An annular eclipse on film
- Round
- Theory
- Points
- 20
- Level
- Bronze
- Taught in
- Section 6.4
Adapted from IOAA 2008 (Bandung), theory problem S11. We have restated it in our own words and kept the original data. The official solution takes the diameters of the Sun and the Moon as 1 392 000 km and 3476 km, which we state. The solution was last checked on 23 October 2026.
A photograph of the annular eclipse of 22 August 1998, seen from Dumai in Indonesia, was taken on 35 mm film through a telescope of aperture 10 cm and focal ratio 15. On the film the Sun's disc is 13.817 mm across and the Moon's is 13.235 mm. Taking the diameters of the Sun and the Moon as 1 392 000 km and 3476 km, find the distances of the Sun and the Moon from the observer, and the percentage of the Sun's disc covered by the Moon at mid-eclipse.
- The focal length is
cm, so the plate scale is ″ per mm (Section 5.2). - The Sun's disc is
″, or 31.67′, across. Its distance is divided by this angle in radians, km. - The Moon's disc is
″, or 30.33′, across, so its distance is divided by this angle in radians, about 394 000 km. - At mid-eclipse the Moon is centred on the Sun, so the covered fraction is the ratio of the areas,
.
AnswerThe Sun was
This problem also appears among the olympiad problems of Section 6.4, The Moon's orbit and eclipses, which teaches the ideas it uses. Equation and figure numbers refer to the course.