Photons from the faintest stars
- Round
- Theory
- Points
- 10
- Level
- Bronze
- Taught in
- Section S4
Adapted from IOAA 2009 (Tehran), theory problem 2. We have restated it in our own words and kept the original data, adding the Sun's apparent magnitude and the solar constant from the IOAA 2025 data sheet. The solution was last checked on 16 October 2026.
A main-sequence star like the Sun has an apparent magnitude of 6, about the faintest that the naked eye can see. Estimate how many photons from it enter the eye each second. Assume that the pupil of the eye is 6 mm across and that all the star's light has a wavelength of 550 nm. The Sun has an apparent magnitude of −26.74, and its light brings 1361 W m⁻² to Earth. A larger magnitude means a fainter star, and 5 magnitudes are a factor of 100 in brightness.
-
The star is
magnitudes fainter than the Sun. It has the same spectrum as the Sun, so all the energy it brings is smaller by the same factor as its visible brightness, and the energy it brings to each square metre is -
A photon of wavelength 550 nm carries
J, so about photons cross each square metre every second. -
The pupil has an area of
m², so the eye receives about 8500 photons each second.
AnswerAbout 8500 photons a second, or roughly
This problem also appears among the olympiad problems of Section S4, Physics toolkit, which teaches the ideas it uses. Equation and figure numbers refer to the course.