Standardising type Ia supernovae
- Round
- Data analysis
- Points
- 50
- Level
- Silver
- Taught in
- Section D10
Adapted from IOAA 2016 (Bhubaneswar), data-analysis problem 3. We have restated it in our own words and kept the original data. The solution was last checked on 20 October 2026.
A type Ia supernova brightens and then fades along a light curve whose shape is nearly the same for all of them, which makes them useful for measuring the distances of faraway galaxies. To compare their light curves, we first turn every observed interval of time
The table gives three supernovae, with the
| SN 2006TD | SN 2006IS | SN 2005LZ | |
|---|---|---|---|
| 34.27 | 35.64 | ||
| 4515 | 9426 | 12 060 | |
| −15 | 19.41 | 18.35 | 20.18 |
| −10 | 17.48 | 17.26 | 18.79 |
| −5 | 16.12 | 16.42 | 17.85 |
| 0 | 15.74 | 16.17 | 17.58 |
| 5 | 16.06 | 16.41 | 17.72 |
| 10 | 16.72 | 16.82 | 18.24 |
| 15 | 17.53 | 17.37 | 18.98 |
| 20 | 18.08 | 17.91 | 19.62 |
| 25 | 18.43 | 18.39 | 20.16 |
| 30 | 18.64 | 18.73 | 20.48 |
(a) Find
(b) Taking the factor
(c) Find
(d) Find the absolute magnitudes at peak of SN 2006TD and SN 2006IS, and from them the constants
(e) Find the absolute magnitude at peak and the distance modulus of SN 2005LZ. (4 points)
(f) From the distance modulus of SN 2005LZ, estimate the Hubble constant
-
The redshifts
are 0.0151, 0.0314 and 0.0402, so the observed intervals are multiplied by , which is 0.9852, 0.9695 and 0.9613. For SN 2006TD, for example, the observations at −15 and +30 days become −14.78 and +29.55 days in its galaxy. -
The peaks are at magnitudes 15.74, 16.17 and 17.58, so
is the time at which the curves reach 17.74, 18.17 and 19.58. Joining neighbouring points by straight lines, these times are 16.66, 22.02 and 18.93 days after the peaks. -
The stretch makes every
equal to the 22.02 days of SN 2006IS, so and . Multiplying each by its factor, the observation of SN 2006TD at +30 days, at 29.55 days in its galaxy, moves to days, and that of SN 2005LZ, at 28.84 days in its galaxy, to days. Plotted against , the three curves fall on one shape, offset from each other only in magnitude. -
The absolute magnitudes at peak are
and . Then -
For SN 2005LZ,
, and its distance modulus is . -
Its distance is
pc, which is 206.1 Mpc, so km/s per Mpc. Its inverse, with 1 Mpc km, is s, or 16.7 billion years. -
As a check, SN 2006TD, which fades fastest, is also the faintest at its peak, as for real type Ia supernovae. The first two supernovae, with their given distance moduli, give
of 63 and 70 km/s per Mpc, so single supernovae scatter widely, which is why a real measurement averages many of them.
AnswerThe stretch factors are
This problem also appears among the olympiad problems of Section D10, Problems for Chapter D, which teaches the ideas it uses. Equation and figure numbers refer to the course.