The rising Sun through the air
- Round
- Theory
- Points
- 10
- Level
- Silver
- Taught in
- Section 2.6
Adapted from IOAA 2018 (Beijing), theory problem 3. We have restated it in our own words and kept the original data. The original statement of (a) is unclear about where the distances are measured from, and we measure them from the centre of the disc as seen, the reading for which the official answer holds. The solution was last checked on 17 October 2026.
Consider sunrise at Beijing (
(a) Just after sunrise, let
(b) By how much does the air make the top edge of the Sun appear earlier than it would without an atmosphere? Take the refraction near the horizon as 35′, and consider only the daily motion of the Sun. [6 points]
- (a) Refraction lifts every point of the disc, but the lower edge, nearest the horizon, is lifted most and the upper edge least. Seen from the centre of the lifted disc, both are moved towards it, the lower edge more, so
is the smallest and is next. The left and right edges are at the height of the centre and are lifted by the same amount, so they keep their distance from it. - (b) Without the air, the top edge would appear when it reached the horizon. With the air, it appears when it is still 35′ below, so the difference in time is the time the Sun takes to rise by 35′.
- At the equinox the Sun rises due east, where
, so by (2.14) it rises at per hour, or 11.49′ per minute. Rising 35′ takes minutes.
Answer(a)
This problem also appears among the olympiad problems of Section 2.6, Sunrise, sunset and twilight, which teaches the ideas it uses. Equation and figure numbers refer to the course.