The chimney at Tiszaújváros
- Round
- Theory
- Points
- 19
- Level
- Silver
- Taught in
- Section 2.8
Adapted from IOAA 2019 (Keszthely), theory problem 6. We have restated it in our own words and kept the original data. We have left out part (b) of the original, which needs the satellite images, so parts (b) and (c) here are parts (c) and (d) of the original. The solution was last checked on 17 October 2026.
The third tallest structure in Hungary is the chimney of a power station near the town of Tiszaújváros. The two Sentinel-2 satellites photograph each area every few days, always at the same local time to within a few minutes, with a resolution of 10 m. One image of the chimney was taken on 29 June and another on 16 December, close to the two solstices. On the two images its shadow is 125 m and 780 m long.
(a) On which of the two dates do we expect the shadow to be longer? [1 point]
(b) Estimate the height of the chimney from the two lengths of its shadow. For this part only, assume that both images were taken at local noon. [16 points]
(c) Which of the following could affect the accuracy of the height found in (b)? More than one may be correct. (A) The flattened shape of Earth. (B) The limited resolution of the images and the blurred edge of the shadow. (C) The height of the base of the chimney above sea level. (D) Changes in the tilt of Earth's axis through the year. (E) Refraction in the atmosphere. [2 points]
-
(a) At the same time of day the Sun is lower in December than in June in the northern hemisphere, so the shadow is longer on 16 December. The shadow is
m on 29 June and m on 16 December. -
(b) The chimney, of height
, and its shadow make a right-angled triangle, so the Sun's altitudes and on the two dates are given by and . -
At noon the Sun's altitude is
(Section 1.4), so at the two solstices the altitudes differ by twice the obliquity, , at any latitude. The official solution rounds this to 45°, which makes , and we follow it. -
By the formula for the tangent of a difference,
which rearranges to the quadratic equation
, here . -
Its roots are
, which gives 426 m or 229 m. -
If the chimney were 426 m tall, the December Sun would have been
high. Hungary is at about 47° N, where the December Sun is never higher than , so the chimney is 229 m tall. -
(c) The answers are (B) and (E). The edge of the shadow can only be found to about a pixel, 10 m, and refraction raises the low December Sun by about 3′. Earth's flattening and the height of the ground do not change the Sun's altitude enough to matter, and the tilt of Earth's axis stays the same through the year.
Answer(a) The shadow is longer on 16 December. (b) The chimney is about 230 m tall. (c) The answers are (B) and (E). The chimney is in fact 250 m tall. The result is very sensitive to the angle used, since a change of 1° in
This problem also appears among the olympiad problems of Section 2.8, Problems for Chapter 2, which teaches the ideas it uses. Equation and figure numbers refer to the course.