A telescope to see a black hole
- Round
- Theory
- Points
- 10
- Level
- Bronze
- Taught in
- Section 10.2
Adapted from IOAA 2019 (Keszthely), theory problem 3. We have restated it in our own words and kept the original data. The problem takes the radius of the shadow to be 3 Schwarzschild radii, a little more than the true 2.60, and the mass of Sagittarius A* to be 3.6 million solar masses, less than the 4.3 million measured since. We keep its values. The solution was last checked on 23 October 2026.
The Event Horizon Telescope imaged the shadow of the black hole at the centre of the galaxy M87 at a wavelength of 1.3 mm. Take the radius of the shadow to be 3 Schwarzschild radii.
(a) How large must a telescope be to resolve the shadow of a black hole of mass
(b) Give this size in Earth radii for (i) the black hole of M87, of
(c) Which technique makes such a telescope possible: (A) gravitational lensing by dark matter, (B) interferometry with an array of radio telescopes, (C) slowing photons in a dense medium, (D) correcting the distortion of the incoming wavefront, or (E) focusing neutrinos with strong electromagnetic fields? (2 points)
- (a) The shadow subtends
. By (5.7) a telescope of diameter resolves it if is less than this, so - (b) For M87,
m and m, so km, which is 1.12 Earth radii. For Sagittarius A*, m and m, so km, which is 1.0 Earth radius. - (c) No single dish can be as large as Earth, but radio dishes spread over Earth and combined as an interferometer resolve as finely as one dish as wide as the distance between them (Section 5.7). The answer is (B).
Answer(a)
This problem also appears among the olympiad problems of Section 10.2, Black holes, which teaches the ideas it uses. Equation and figure numbers refer to the course.