The limits of accretion
- Round
- Theory
- Points
- 20
- Level
- Silver
- Taught in
- Section 10.4
Adapted from IOAA 2022 (Kutaisi), theory problem 10. We have restated it in our own words and kept the original data. In part (f) the official solution keeps the angular speed of the orbit fixed while the separation changes, which gives a change in separation four times too small. Using Kepler's third law, as we do, gives the same conclusion with the right size. The solution was last checked on 23 October 2026.
A compact object of mass
is the Thomson cross-section. Although the force acts on the electrons, it acts on whole atoms.
(a) Find the Eddington luminosity
(b) An object accretes gas with a luminosity equal to the Sun's. What is its smallest possible mass, in solar masses? (4 points)
(c) The gas starts far away and its energy of falling is turned into radiation. Find the accretion luminosity in terms of
(d) Show that the greatest steady rate of accretion does not depend on the mass of the object. (2 points)
(e) Find this rate, in solar masses a year, for an object of radius
(f) The object, of mass
- (a) At distance
the intensity is , so the push on an atom is and the pull is . They balance at , with , as in (10.12). - (b) With
m², the mass is at least which is solar masses. - (c) Each kilogram releases
, so . - (d) Setting
gives , in which has cancelled. - (e) For
m this is kg/s, or kg a year, which is 0.018 solar masses a year. - (f) The angular momentum of the orbit is
, and Kepler's third law gives , so . With and fixed, . - When
gains and loses it, , so This is positive when is more than .
Answer(a)
This problem also appears among the olympiad problems of Section 10.4, Accretion and the Eddington limit, which teaches the ideas it uses. Equation and figure numbers refer to the course.