Problems for Chapter 13
- Builds on
- Sections 13.1 to 13.8
- Reading time
- 50 min
- Exercises
- 0
- Olympiad problems
- 2
The past problems in the earlier sections of this chapter each used one or two ideas at a time. The two in this section join them up. The first, from IOAA 2018, follows the Universe back from today to the first second, using the Friedmann equation, the way each kind of energy thins out, the background radiation and a little dimensional analysis. It is long, at 75 points, but every part is short and most parts use one result of the chapter. The second is a thought experiment in which light bounces off a mirror far from the Sun while the space between them grows.
13.9.1From textbook to olympiad
Part (i) of the first problem below asks for the redshift at which matter and radiation had equal densities, in terms of
- We start by drawing it. On a graph of the logarithm of density against the logarithm of the scale factor, matter is a straight line of slope
and radiation a steeper line of slope , as in Figure 13.3. Going back in time, the radiation line climbs faster and crosses the matter line. The crossing is the moment we want. - We name the physics. Matter thins out as
and radiation as ((13.7)), so the ratio of radiation to matter grows as . - We work backwards from the target. At equality
, so . Everything now rests on finding . - We use every given. The problem gives the energy density of blackbody radiation, the temperature of the background today and the extra 68 per cent from neutrinos. The first two give the density of photons, the critical density turns it into
, and the neutrinos multiply it by 1.68. Because the answer is asked for in terms of , we keep km/s/Mpc as a symbol. - We check the answer. With
and the result is a redshift of about 3500. This is close to the 3570 found in Section 13.4, whose model has a slightly smaller density of radiation, and to the crossing in Figure 13.3.
2018The thermal history of the Universe75 points
Adapted from IOAA 2018 (Beijing), theory problem 11. We have restated it in our own words and kept the original data. The solution was last checked on 21 October 2026.
The Friedmann equation for a uniform universe can be written
where
(a) What are the dimensions of
(b) The critical density is the density of matter that a flat universe with no radiation and no dark energy needs for its expansion. Express it in terms of
(c) With the density parameters
(d) Each component also obeys the fluid equation
(e) The density of the cosmological constant does not change. Its pressure is
(f) The Planck time, before which our physics needs a quantum theory of gravity, is a combination of
(g) The Planck length is
(h) The energy density of blackbody radiation is
(i) Neutrinos add 68 per cent to the energy density of the photons, so
(j) Neutrinos stopped interacting with the rest of the matter when
- (a)
is a rate, with dimensions of 1/time. The Hubble time is s, or 14.47 Gyr ((13.2)). - (b) Setting
, and to zero leaves , so ((13.6)), which is kg/m³ today. - (c) Dividing the Friedmann equation by
gives from the first term, so and . - (d) With
the fluid equation becomes , so and , since . - (e) With
the fluid equation leaves , so . A cosmological constant has a negative pressure. - (f) The dimensions are
, and . Matching the powers of M, L and T in to a time gives , and , so and . Then s. - (g) Setting
gives kg, and GeV. - (h) The energy density of radiation is
, which goes as by part (d). It also goes as , so ((13.14)). - (i) At equality
, so . The photons have with , which gives . With the neutrinos, , so . - (j) At 1 MeV,
, so . With from the given , . Then and s.
Answer(a) 1/time, and 14.47 Gyr. (b)
2020A mirror in an expanding universe10 points
Adapted from GeCAA 2020 (Estonia, held online in place of the IOAA), theory problem 3. We have restated it in our own words and kept the original data. The solution was last checked on 21 October 2026.
A cosmologist imagines measuring
(a) Find
(b) The mirror is placed near Vega, whose parallax is 0.125″. Estimate how long the experiment takes. (3 points)
- Without expansion the light would cover
in the time . During the flight, the space it crosses grows by , and on average by . So . - Solving for
gives . - For Vega,
pc. The expansion over 8 pc is tiny, so s.
Answer(a)